Stability of a circular orbit in a central force field
There are at least two approaches to the stable circular
orbits for the two-body problem in a central potential U(r).
- Lagrange's equations
- Effective potential energy
Lagrange's equations. Lagrangian L = T-U
- L = 1/2 m (r-dot^2 + r^2 theta-dot^2) - U(r)
- m = reduced mass = m1 m2/(m1+m2)
- equations of motion
- m r-dot-dot = m r theta-dot^2 -U'(r)
- d/dt(mr^2 theta-dot) = 0 => mr^2 theta-dot = l = angular
momentum
- substitute in the mr-dot-dot equation for theta-dot and
get
- m r-dot-dot = l^2/mr^3 -U'(r)
- For a circular orbit, we need r-dot-dot = 0 at
r=ro
- this requires mr theta-dot^2 = U'(ro), or that (substituting
for theta-dot)
- l^2/(mro^3) = U'(ro)
- For a stable circular orbit, we need small oscillations
to occur around ro
- let r=ro + x, where x<<ro
- then the equation of motion becomes
- m x-dot-dot = l^2/(m (ro+x)^3) -U'(ro+x)
- we binomially expand the first term on the rhs and taylor-expand
the 2nd.
- this gives m x-dot-dot = l^2/(mro^3)(1-3 x/ro) -U'(ro)
- x U''(ro).
- cancelling the leading terms (due to circular orbit condition)
gives
- m x-dot-dot = - x [3l^2/(mro^4) + U''(ro)] .
- this will oscillate if the expression in square brackets
is greater than zero.
- substituting from the circular orbit conditon gives
3/r U'(r) + U''(r) >0 for a stable circular orbit
Effective potential energy, Ueff(r)
- E = 1/2 m (r-dot^2 + r^2 theta-dot^2) +U(r)
- substitute for theta-dot from angular momentum in energy
equation and get
- E = m/2 r-dot^2 + l^2/(2mr^2) + U(r)
- Since the last two terms are functions of r, we can regard
them as an 'effective potential'
- Ueff = l^2/(2mr^2) + U(r)
- For a circular orbit we need Ueff'(r) = 0 at r=ro
- This requires -l^2/(mr^3) + U'(r) = 0
- For a stable circular orbit we need Ueff''(r)
>0 at r=ro
- this requires 3l^2/(mr^4) + U''(r) >0 at r=ro
- substituting in from the circular orbit condition we
get
3/r U'(r) + U''(r) >0 for a stable orbit
These two approaches give the same conditions for a
stable circular orbit.
- The effective potential approach fits right into what
we did before for frequency of small oscillations near a potential minimum
- The expansion r = ro+x is good in that it reminds us
of the method of series expansions to solve problems.